A spy satellite is in circular orbit around Earth. It makes one revolution in 6.01 hours.

how high above earth?
acceleration?

1 answer

change time to seconds for the period.

v=2PI h/period
v^2=(2PI)^2/period^2

v^2/r= 9.8*(re^2/r^2) where r is the orbital radius.

solve for r, then altitude is r-re.