h = 4.6 m.
V1 = 16 m/s.
V2 = 26 m/s.
g = 9.81 m/s^2
h = 0.5g*t^2
Solve for t = Fall time.
d = (V2-V1)*t = Distance apart.
A spy in a speed boat is being chased down a
river by government officials in a faster craft.
Just as the officials’ boat pulls up next to the
spy’s boat, both boats reach the edge of a 4.6
m waterfall. The spy’s speed is 16 m/s and
the officials’ speed is 26 m/s.
How far apart will the two vessels be when
they land below the waterfall? The acceleration
of gravity is 9.81 m/s
2
.
2 answers
Same answer.