h = 0.5g*t^2 = 7.8 m.
4.9*t^2 = 7.8
t^2 = 1.59
Tf = 1.26 s. = Fall time for each boat.
d1 = V1*t = 22m/s * 1.26s. = 27.76 m.
d2 = V2*t = 11m/s * 1.26s. = 13.88 m.
d1-d2 = 27.76 - 13.88 = 13.72 m. Apart.
A spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials' boat pulls up next to the spy's boat, both reach the edge of a 7.8 m waterfall. If the spy's speed is 11 m/s and the officials' speed is 22 m/s, how far apart will the two vessels be when they land below the waterfall?
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