A spring with 50 N/m hangs vertically next to a ruler. The end of the spring is next to the 21-cm mark on the ruler.If a 2.5-kg mass is now attached to the end of the spring, where will the end of the spring line up with the ruler marks?

Answer 1

F = m * g = 2.5kg * 9.8N/kg = 24.5 N.

d = (24.5N/50N) * 1m = 0.49m. = 49 cm.

End of spring = 21 + 49 = 70 cm.

Answer 2

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