A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N?(1 point)

Responses

The acceleration decreases to a quarter of its original value, or about 2.13 m/s2.
The acceleration decreases to a quarter of its original value, or about 2.13 m/s 2 .

The acceleration decreases to a quarter of its original value, or about 0.13 m/s2.
The acceleration decreases to a quarter of its original value, or about 0.13 m/s 2 .

The acceleration increases to four times its original value, or about 0.13 m/s2.
The acceleration increases to four times its original value, or about 0.13 m/s 2 .

The acceleration increases to four times its original value, or about 2.13 m/s2.

1 answer

To determine how the acceleration changes with different net forces acting on the object, we can use Newton's second law of motion, which states:

Fnet=ma

Where:

  • Fnet is the net force,
  • m is the mass,
  • a is the acceleration.

First, let's calculate the acceleration with the original net force of 0.8 N:

Given:

  • Fnet=0.8,N
  • m=1.5,kg

Using the formula, we can solve for acceleration a:

a=Fnetm=0.8,N1.5,kg=0.81.50.533,m/s2

Now, let's calculate the acceleration with the new net force of 0.2 N:

Given:

  • Fnet=0.2,N
  • m=1.5,kg

Again using the formula, we can solve for the new acceleration a:

a=Fnetm=0.2,N1.5,kg=0.21.50.133,m/s2

Now we can compare the two accelerations. The initial acceleration was approximately 0.533 m/s² and the new acceleration is approximately 0.133 m/s², which is indeed a quarter of the original acceleration:

0.133,m/s20.533,m/s24

Therefore, the correct response is:

The acceleration decreases to a quarter of its original value, or about 0.13 m/s².