a spring of natural length 30.0cm is stretched to 35.0cm by a load of 15N. calculate

Question

(i)the extension produced
(ii)the elastic constant of the spring
(iii)work done in stretching the spring

Answer 1

(i) The extension produced is given by the difference in length before stretching and after stretching:
Extension = 35.0cm - 30.0cm = 5.0cm = 0.05m

(ii) The elastic constant of the spring can be calculated using Hooke's Law, which states that F = kx, where F is the force applied, k is the elastic constant, and x is the extension produced. Rearranging the equation, we get:
k = F/x

Substitute in the values:
k = 15N / 0.05m
k = 300 N/m

(iii) The work done in stretching the spring can be calculated using the formula:
Work = 0.5 * k * x^2

Substitute in the values:
Work = 0.5 * 300 N/m * (0.05m)^2
Work = 0.5 * 300 N/m * 0.0025 m
Work = 0.375 J

Therefore, the work done in stretching the spring is 0.375 Joules.