A spring of natural length 1.5m is extended 0.055cm by force of 0.8N, what will it length be when the applied force is 3.2N

Answer 1

area you sure you mean .055 cm and not .055 m ?
F = k x
.8 = k *.00055

x + 1.5 = F/k + 1.5 = 3.2 *.00055/.8 + 1.5

Answer 2

0n