A spring 20cm long is stretched to 25cm by a load of 50N. What will be the length when stretched by 100N, assuming that the elastic limit is not exceeded.

Answer 1

100N is twice as much as 50N
so the spring will be stretched twice as far.

Answer 2

25-20 = 5 cm increase.
50/5 = 100/x
X = ___ cm increase.
Length = 20+x.