a spring 20cm long is streched to 25cm by a load of 50n what will be it length when streched by 100n assuming that the elastic limit is not reached show soving

Answer 1

K=F/e
K=50/25-20
K=10N/cm

e=F/K
e=100/10
e=10
Therefore new length =20 + 10 = 30cm

Answer 2

The elongation is directly proportional to force.
50n gives 5cm elongation
100N gives 10cm, or a length of 30 cm