A spiral spring of natural length of 30.0cm and a constant force of 20N/m is compressed to 20cm. Calculate the energy stored in the spring.

Answer 1

30 cm - 20 cm = 10 cm = .1 meter

F = k x
20 = k (.1)
so
k = 200

E = (1/2) k x^2
= (1/2)(200)(.01)
= 1 Joule

Answer 2

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