A spiral spring extends from a length of 10.00cm to 10.01cm when a force of 20N is applied on it .calculate the force constant of the spring

Answer 1

To calculate the force constant of the spring, we can use Hooke's Law:

F = kx

Where:
F = force applied on the spring (20N)
k = force constant of the spring
x = extension of the spring (10.01cm - 10.00cm = 0.01cm = 0.0001m)

Substitute the values into the equation:

20N = k * 0.0001m

Now solve for k:

k = 20N / 0.0001m
k = 200,000 N/m

Therefore, the force constant of the spring is 200,000 N/m.