The force constant of a spring is given by Hooke's Law, which states that the force applied on the spring is proportional to the extension or compression of the spring. Mathematically, Hooke's Law is expressed as:
F = -kx
where F is the force applied on the spring, k is the force constant of the spring, and x is the displacement of the spring from its equilibrium position.
Given that the spring extends from a length of 10.00 cm to 10.01 cm when a force of 20 N is applied on it, we can calculate the displacement of the spring as follows:
x = 10.01 cm - 10.00 cm
x = 0.01 cm = 0.0001 m
Substitute the values of F = 20 N and x = 0.0001 m into Hooke's Law to calculate the force constant k:
20 N = - k * 0.0001 m
k = -20 N / 0.0001 m
k = -200,000 N/m
Therefore, the force constant of the spring is 200,000 N/m.
A spiral spring extends from a length of 10.00 cm to 10.01 , when force of 20 N is applied on it , calculate the force constant of the spring
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