A spinning wheel steadily slows from an initial angular velocity of 1.65 rev/s to 0.485 rev/s in 12.2 s.

Question

A spinning wheel steadily slows from an initial angular velocity of 1.65 rev/s to 0.485 rev/s in 12.2 s.
(a) Calculate the wheel's angular acceleration in radians per second squared. 
  rad/s2

(b) What angle does it go through during that time? 
  rad

Henry · Answer

Vo=1.65 rev/s * 6.28rad/rev=10.362 rad/s V=0.485rev/s * 6.28rad/rev = 3.05 rad/s a. a = (V-Vo)/t