nope. You have to account for both events.
P(odd) = 3/4
P(even) = 1/4
so, P(odd,even) = 3/4 * 1/4
A SPINNER WITH FOUR EQUAL SECTIONS NUMBERED 3,5,7 AND 8 IS SPUN TWICE. WHAT IS THE PRBABILITY THAT AN ODD NUMBER IS SPUN THE FIRST TIME AND AN EVEN NUMBER IS PUN THE SECOND? IS THE ANSWER 3/4? IS IT THAT EASY OR NOT?
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