A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.

Question

Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14

Based on the table, for what probability can you expect the spinner to not land on B?
0.10
0.33
0.40
0.66

Answer 1

To find the probability that the spinner does not land on B, we need to calculate the combined frequencies of outcomes that do not include B.

From the table:
- Outcomes where B is not selected: A, A (15) + A, C (10) + C, A (11) + C, C (14) = 50

The total number of times the spinner was spun twice is 125.

Therefore, the probability that the spinner does not land on B is 50/125 = 0.40.

So, the correct answer is 0.40.