A spinner has 3 different colors: blue, red and green. If the probability of getting blue is ⅓, the probability of getting red is ¼. If the spinner has 12 sections, how many green sections are there?

Answer 1

Let x be the number of green sections on the spinner.

Since the total number of sections on the spinner is 12, the probability of getting green is x/12.

We are given that the probability of getting blue is 1/3 and the probability of getting red is 1/4.

Therefore, the total probability from all three colors should be 1:

1/3 (blue) + 1/4 (red) + x/12 (green) = 1

Multiplying through by 12 to eliminate fractions:

4 + 3 + x = 12

7 + x = 12

x = 12 - 7

x = 5

Therefore, there are 5 green sections on the spinner.