A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.890 m/s at an angle of 36.0° above the table, and it lands on the magazine 0.0660 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

Answer 1

well, the vertical position (in meters) of the spider at time t is

y(t) = 0.890 sin 36° t - 4.9t^2
= 0.523t - 4.9t^2

So, what is y(0.0660)?