total energy at bottom=increase in PE
1/2 mv^2+1/2 I V^2/r^2=mg*2.2sin30
solve for I.
A spherically symmetric object with radius R= 0.51m and mass of M= 3.5kg rolls without slipping accross a horizontal surface with velocity of V = 4.4m/s. It then rolls up an incline with an angle of 30 degrees and comes to rest a distance d = 2.2m up the incline, before rolling back down. Find the moment of inertia of this object about an axis through its center of mass.
1 answer