Question

A spherical steel ball bearing has a diameter of 2.540 cm at 24°C.

(a) What is the diameter when its temperature is raised to 82°C?


(b) What temperature change is required to increase its volume by 1.1%?



I got the first answer right.

i am having trouble understanding how to figure out how much the diameter is increased by when i know how much the total volume is increased by.....

Answer 1

Take the cube root of the volume increase factor
(1.011)^1/3 = 1.0036533.

That will be the diameter increase factor. The increase will be 0.3653%

Answer 2

The temperature of the air outside on a cool morning is 11„aC.What is
this temperature on the Kelvin scale?