Take the cube root of the volume increase factor
(1.011)^1/3 = 1.0036533.
That will be the diameter increase factor. The increase will be 0.3653%
A spherical steel ball bearing has a diameter of 2.540 cm at 24°C.
(a) What is the diameter when its temperature is raised to 82°C?
(b) What temperature change is required to increase its volume by 1.1%?
I got the first answer right.
i am having trouble understanding how to figure out how much the diameter is increased by when i know how much the total volume is increased by.....
2 answers
The temperature of the air outside on a cool morning is 11„aC.What is
this temperature on the Kelvin scale?
this temperature on the Kelvin scale?
1 answer