A spherical balloon remains spherical as it is slowly inflated. The radius of the balloon r (in cm) at time t (in seconds) satisfies the differential equation.

Dr/dt = k/r^2

where k is a positive constant.

When the radius is 3 cm, the radius is increasing at the rate of 5/36pi use this fact to find k.

1 answer

?? Just plug in the numbers:

at r=3,
dr/dt = 5π/36 = k/9
k = 5π/4