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A spherical balloon is inflated so that its volume is increasing at the rate of 3.2 ft3/min. How rapidly is the diameter of the balloon increasing when the diameter is 1.1 feet?

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V=4/3 PI (D/2)^3=1/6 PI D^3

dV/dt=PI/6 *3D^2 * dD/dt
solve for d(diameter)/dt

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