dV/dS = (dV/dt) / (dS/dt) = (4πr^2 dr/dt)/(8πr dr/dt) = r/2
So just find r when V = 50
A spherical balloon is being inflated. Given that the volume of a sphere in terms of its radius is V(r) =4/3 πr^3 and the surface area of a sphere in terms of its radius is S(r) = 4 πr^2, estimate the rate at which the volume of the balloons is changing with respect to its surface area when the surface area measures 50 cm^2.
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Can you show that too
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