Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A sphere of mass M is supported by a string that passes over a pulley at the end of a horizontal rod of length L. The string ma...Asked by Anonymous123
A sphere of mass M is supported by a string that passes over a pulley at the end of a horizontal rod of length L . The string makes an angle θ with the rod. The fundamental frequency of the standing waves in the portion of the string above the rod is f. Find the mass of the portion of the string above the rod. (Use any variable or symbol stated above along with the following as necessary: g.)
Answers
Answered by
bobpursley
length of string vibrating=half wave length.
You need to find tension
Summing moments about the fixed end of the rod.
-MgL+tension*L*(sin(90-theta))=0
Now look at stringl forces on the pulley
tension=Mg
so tension*L(sin(90-theta)-1)=0
Now we need to covert L to length of string
lengthstring=L/cos(90-theta)
or L=lengthstring*cos( )
tension*lengtthstring*cos( )(sin( )=0
now to the wave equation: f*wavelength=speed
we can relate speed to tension and mass/length, and wavelength to the lengthstsring, and from that find mass/length.
Can you handle it from here? (check my work)
You need to find tension
Summing moments about the fixed end of the rod.
-MgL+tension*L*(sin(90-theta))=0
Now look at stringl forces on the pulley
tension=Mg
so tension*L(sin(90-theta)-1)=0
Now we need to covert L to length of string
lengthstring=L/cos(90-theta)
or L=lengthstring*cos( )
tension*lengtthstring*cos( )(sin( )=0
now to the wave equation: f*wavelength=speed
we can relate speed to tension and mass/length, and wavelength to the lengthstsring, and from that find mass/length.
Can you handle it from here? (check my work)
Answered by
Anonymous123
Yes! :) Thank you so much for your help!
There are no AI answers yet. The ability to request AI answers is coming soon!