A sphere of mass 0.4kg moving on a smooth billiard table hit a stationary sphere of mass 0.8kg and was brought to rest. Calculate the velocity at which the second sphere tends to move and loss in K.E energy

1 answer

momentum is conserved,
.4V=.8v'

v'=1/2 V

new KE= 1/2 .8 (v'^2)1/2*.8*(1/2 v)^2
= 1/2*.8*1/4* v^2
loss of KE= old ke-new ke
= .4/2 v^2-.1/8 v^2
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