a speedster traveling at a constant speed of 120 km/h passes a waiting police car which immediately starts from rest with a constant acceleration of 2.5 m/s^2.how long will it take the police car to catch the speedster?what is the distance that the speedster would have travel when caught by the police?

3 answers

just see when the distances are equal:

120km/hr = 100/3 m/s, so

100/3 t = 2.5/2 t^2
t = 80/3

Now I expect you can handle the rest . . .
I DO APPREACIATE YOUR HELP,BUT AM STILL LITTLE CONFUSED
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