A speeding car is traveling at a constant 30.0 m/s when it passes a stopped police car. The police car accelerates at 7.0 m/s^2. a)how far will the police travel to catch up to the speeder? b) how fast will it be going when it catches up?

Answer 1

vt=at^2/2
t=2v/a=8.6
s=vt=30•8.6=258 m