a specific gravity bottle of mass 40 g, mass when filled with water is 90 g, mass when filled with liquid is 80 g and mass when it contains 50 g of powder is 120 g. calculate the relative density of powder

Answer 1

To calculate the relative density of the powder, we first need to calculate the volume of the liquid displaced by the powder.

The mass of the specific gravity bottle when filled with water is 90g, and the mass of the empty bottle is 40g. Therefore, the mass of water in the bottle is 90g - 40g = 50g. Using the density of water (1 g/cm^3), we can calculate that the volume of water displaced by the bottle is 50 cm^3.

Similarly, the mass of the liquid in the bottle is 80g, so the volume of the liquid displaced by the bottle is 80 cm^3.

Now, the mass of the powder in the bottle is 120g, and the mass of the liquid in the bottle is 80g. Therefore, the mass of the powder is 120g - 80g = 40g.

The volume of the powder can then be calculated as:
Volume of powder = Volume of liquid + Volume of water - Volume of bottle
Volume of powder = 80 cm^3 + 50 cm^3 - 100 cm^3 = 30 cm^3

The relative density of the powder can now be calculated as the mass of the powder divided by the volume of the powder:
Relative density = Mass of powder / Volume of powder
Relative density = 40g / 30 cm^3
Relative density = 1.33 g/cm^3

Therefore, the relative density of the powder is 1.33 g/cm^3.