Given that the point on the unit circle is \((x, y)\) where \(y = \frac{\sqrt{2}}{2}\), we know that the equation of the unit circle is \(x^2 + y^2 = 1\).
Substituting \(y\) into the equation:
\[ x^2 + \left(\frac{\sqrt{2}}{2}\right)^2 = 1 \]
Calculating \(\left(\frac{\sqrt{2}}{2}\right)^2\):
\[ \left(\frac{\sqrt{2}}{2}\right)^2 = \frac{2}{4} = \frac{1}{2} \]
Now substituting this value back into the unit circle equation:
\[ x^2 + \frac{1}{2} = 1 \]
Subtract \(\frac{1}{2}\) from both sides:
\[ x^2 = 1 - \frac{1}{2} = \frac{1}{2} \]
Taking the square root of both sides gives:
\[ x = \sqrt{\frac{1}{2}} = \frac{\sqrt{2}}{2} \]
Since we are in Quadrant 1, where \(x\) is positive, we take the positive root:
Thus, the x-coordinate is:
\[ x = \frac{\sqrt{2}}{2} \]
Therefore, the correct answer is:
\(\sqrt{2}/2\)
Answer: \(\sqrt{2}/2\)