A speaker has a diameter of 0.303 m. (a) Assuming that the speed of sound is 343 m/s, find the diffraction angle è for a 1.80-kHz tone. (b) What speaker diameter D should be used to generate a 3.72-kHz tone whose diffraction angle is as wide as that for the 1.80-kHz tone in part (a)?

Answer 1

For circular opening sin(theta) = 1.22 (lambda)/D
To get lambda use v = f (lambda) i.e.
343 = (lambda)/1800.