A space vehicle travelling at a velocity of 6000km/h separates into two parts of mass 1200 kg and 300 kg. The two parts continue moving in the same direction with the lighter section moving at 6200km/h. Making use of the principle of conservation of momentum, determine the velocity of the heavier section after separation
1 answer
6000*(1200+300)=300*6200+1200*V solve for V