A space shuttle is launched from rest. It takes 8.00s to reach 165km/h , and at the end of the first 1.00 min its speed is 1650km/h .

a) what is the avg. acceleration in (m/s2) during the first 8.00 seconds?

b) what is the avg. acceleration in (m/s2) between the 8.00 seconds and the first 1.00 min?

c)vAssuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the shuttle travel during the first 8.00s?

d) Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the shuttle travel during the interval from 8.00s to 1.00min?

3 answers

A. a = v/t 165km / 8s = 20.625 km/h/s

B. t= 60s-8s =52s, V= 1650km/h-165km/h =1485km/h
a=v/t 1485km/h / 8s= 185.625km/h/s

C. d=1/2at^2 1/2 * 20.625 km/h/s * (8s)^2 = 183.333m

D. 60s-8s=52s d=1/2at^2 1/2 * 186.625km/h/s * (52s)^2 = 70.088km
the answers are supposed to be in m/s^2
A. 5.729 m/s^2
B. 51.5625 m/s^2
C. 183.333m
D. 70,088m