The distance from the center of the earth is increased by a factor 1/sqrt(0.93) = 1.0370. That is redundant information; they already tell you the altitude. The numbers are consistent.
You could use Kepler's third law for the period. I assume that your "that" is supposed to be "What"
You can also get the answer by requiring that the centripetal acceleration be 0.93 g, and solve for V.
V^2/R = 0.93 g
R = 250 + Re = ?
(Look up the radius of the earth, Re)
The period P is then given by
V * P = 2 pi R
a space shuttle is in a cic ular orbit at a height of 250 km, where the acceleration os earth,s gravity is 93 percent of its surface value. that is the period of its orbit
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