%by mass = (mass solute/mass solution)*100 = ?
mass solution = 1000gH2O + 59g glucose + 2.3g NaCl.
% glucose = (59/1061.3)*100 = ?
% NaCl = (2.3/1061.3)*100 = ?
% H2O = (1000/1061.2)*100 = ?
% sucrose = 0%
If your prof is picky about the number of significant figures be sure to round the final percent number to the correct number of s.f.
A solution was prepared using 1,00 liter of water, 59 g glucose, and 2,3 g NaCl. One liter of water weighs 1000 grams. The solution needs to be labeled in terms of % glucose and % sucrose.
1 answer
1 answer