A solution was prepared by dissolving 0.163 g of sugar, (C12H22O11 MW = 3423gmol)
in 100.00 mL water. What is the molarity of this solution?
1 answer
You left out a decimal in the MW. It is 342.3 g/mol. 0.163 g is therefore 0.000475 moles. Divide that by 0.100 L to get the molarity (M)in moles/Liter