a solution of sulfur (2.560g) in naphthalene (100g) freezes 0.68K lower the freezing point of pure naphthalene (353.10K). for naphthalene, Kf= 6.8K kg mol. calculatem the molecular formula of the sulfur dissolved in the naphthalene?

Answer 1

delta = Kf*molality
Solve for molality

molality = moles/kg solvent.
Solve for moles

moles = grams/molar mass
solve for molar mass.

Answer 2

so, 0.68K/6.8 K kg mol= 0.1kg/mol (m)
then 0.1/32g/mol= 3.1*10^-3
then (3.1*10^-3)*(2.56g)= 8*10^-3
does that make it S8, i don't get that part.

Answer 3

1st step:
*Find out MB
*If the ans is less than ,64
For eg,
ans=32
So,64/32=2
Hence the formula is S2