Asked by Joe

A solution of calcium nitrate, Ca(NO3)2, reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(aq). When 45.00 mL of 4.8724 x 10-1 M Ca(NO3)2 solution was added to 60.00 mL of 9.9981 x 10-1 M NH4F solution, 1.524 g of CaF2 was isolated.

Calculate the number of moles of Ca(NO3)2 originally present
Answered by DrBob222
See your post below. Same procedure.
Answered by Anonymous
0.5999
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