Ask a New Question

A solution of acetic acid was prepared by mixing glacial acetic acid with water.The solution was 25% of acetic acid by volume.How much glacial axetic acid must be used to prepare 120 mL of desired volume?

1 answer

Glacial acetic acid is about 17.5M
mL1 x %1 = mL2 x %2
mL1 x 17.5 = 120 mL x 25%
mL 1 = ?

Ask a New Question or answer this question.

Similar Questions

Pure acetic acid (HC2H3O2) is a liquid and is known as glacial acetic acid. Calculate the molarity of a solution prepared by
1. 1 answer
Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25°C. Calculate the molarity of a
1. 4 answers
Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25°C. Calculate the molarity of a
1. 2 answers
How many mL of glacial acetic acid would you pipette to prepare a solution of 100mL of 5 M acetic acid solution? (Hint: what is
1. 1 answer

more similar questions