118mL of 0.16M gives 0.118 * 0.16 = 0.01888 moles of KOH
Now the equation tells you how many moles of Ni(OH)2 you will get
convert that to grams.
A solution of 118 mL of 0.160 M KOH is mixed with a solution of 240 mL of 0.230 M NiSO4.
How many grams of this precipitate (Ni(OH)2) form?
I have the balanced equation as 2KOH (aq)+ NiSO4 (aq) ----> K2SO4 (aq) + Ni(OH)2
I don't need the answer but I would really like to know how to do it.
1 answer