a solution of 0.2113 g of water dissolv ed in 25g of a solvent freezes at 11.5 degrees celcius below the freezing point of the solvent. what is the Kf for the solvent?
A)0.735
B)1.36
c)5.39
D)24.5
Help!!!
delta T = Kf*molality
Calculate molality = #mols solute/kg solvent, plug into the first equation and calculate Kf.
Post your work if you need further assistance.
1 answer