A solution is prepared by mixing 90 ml of 5 M HCl and 30 ml of 8 M HNO3. Water is then added until the final volume is 1 L. Calculate the [H+], [OH-], and the pH for this solution.

Answer 1

mols HCl = M x L = ?
mols HNO3 = M x L = ?
M final = total mols/total L
(H^+) = final M
pH = -log(H^+)
(H^+)(OH^-) = Kw = 1E-14