A solution is prepared by mixing 1.00g ethanol (C2H5OH) with 100.0g water to give a final volume of 101.mL. Calculate the molarity, mass percent and mole fraction of ethanol in the solution.

Answer 1

M = mols/L.
mols = g/molar mass = 1.00/46 = ? but check those numbers.
M = mols/0.101 L = ?

% w/w (or m/m) = (mass solute/total mass)*100
% = (1.00/101)*100 = ?

mols ethanol = g/molar mass = ?
mols H2O = g/molar mass = ?
Total mols = mols ethanol + mols H2O = ?
Xethanol = mols ethanol/total mols = ?
XH2O = mols H2O/total mols = ?

Answer 2

Please can I see the answer

Answer 3

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