A solution is prepared by dissolving 10.8 g of ammonium nitrate in enough water to make 100.0 mL of solution. A 10.0 mL portion of this sample is diluted to 50.0 mL total volume. What is the molarity of the final solution?

Answer 1

a number of ways to do this

he must have put 1/10 of 10.8g in the sample, then diluted it to a volume of .050liters

Molarity=10.8/10 * 1/molmass*1/.050

where molmass is the molmass of ammonium nitrate.