A solution is prepared by adding 50ml of 0.050M HCl to 150 ml of 0.10M HNO3. Calculate pH

Answer 1

the two strong acids fully dissociate

divide the total moles of H+ by the total solution volume
... this is the concentration of H+ ... [H+]

pH is the negative logarithm of [H+]

Answer 2

can you show me how

Answer 3

.050 L * .050 M = .0025 moles ... .150 L * .10 M = .015 moles
... total moles H+ ... .0175

total solution volume ... .050 L + .150 L = .20 L

[H+] = .0175 moles / .20 L = ?

pH = -1 * log[H+]