A solution is made by dissolving 3.5 moles of sodium chloride (NaCl) in 155 grams of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution?

Answer 1

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molality = moles/kg solvent
Solve for molality

delta T = i*Kb*molality
Solve for delta T, then boiling point knowing that the normal boiling point for water is 100 C.
i is the van't Hoff factor, which for NaCl = 2.
i was 1 in the previous post.