A solution is made by dissolving 27.8 g of nicotine (Molar Mass = 160 g/mol) in 145 g of cyclohexane (C6H12) to form 142 mL of solution. Calculate the mole fraction of the solute and the molarity, respectively, of this solution.

Question

A solution is made by dissolving 27.8 g of nicotine (Molar Mass = 160 g/mol) in 145 g of cyclohexane (C6H12) to form 142 mL of solution.  Calculate the mole fraction of the solute and the molarity, respectively, of this solution.

DrBob222 · Answer

mols nicotine = grams/molar mass = ? mols C6H12 = grams/molar mass Find total mols. XC6H12 = nC6H12/total mols. M C6H12 = mols C6H12/L solution = ?