It is; however, your calculation gives you pOH. If you want pH, use
pH + pOH = pKw = 14 and solve for pH.
Or you can use (H^+)(OH^-) = Kw = 1E-14
pH = -log(H^+)
pOH = - log(OH^-)
A solution is found to contain 1 x 10-4 OH− ions, determine the pH of this solution.
I did this problem and got 4 but it is not going in as correct.
-log(1*10^-4)=4
3 answers
I did it and got 10 and it is saying that its incorrect
pOH = 4
pH = 10
Or
(H^+) = 1E-14/1E-4 = 1E-10
pH = 10
The data base is wrong or you posted the problem incorrectly. The pH is 10 for the above problem.
pH = 10
Or
(H^+) = 1E-14/1E-4 = 1E-10
pH = 10
The data base is wrong or you posted the problem incorrectly. The pH is 10 for the above problem.
1 answer