A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 265 mL of solution. How many moles of ammonium chloride are present in the resulting solution?

Question

When thinking about the amount of solute present in a solution, chemists report the concentration or molarity of the solution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution described above?

To carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH4Cl?

Answer 1

1. mols NH4Cl - grams/molar mass = ?
2. M = molarity = mols/L
3. M = mols/L. You know M and you know mols, substitute and solve for L. Convert to mL if you wish.
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