a solution is 0.0300 m in Sodium. How many grams of sodium carbonate are necessary to prepare 900.0 ml of this solution?

Question

I don't know where to start on this.

Answer 1

I assume you meant Molarity instead of m molality.

Na2CO3 (aq). If the solution is .03M n Na, it is .015M in sodium carbonate.

masssodumcaronate=.015*molmasssodiumcarb*.900