let x = OH^-
You know (H^+)(OH^-) = Kw = 1E-14
(1000x)(x) = 1E-14
Solve for x
A solution in which [H+] is 1000 times greater than [OH-]
[OH-] = ?M
3 answers
I don't know if I'm reading this right, so I have the 1000x(x)= 1E-14, but doesn't that leave me with 2x on one side and 1E-14 right?
No it doesn't. You're reading it right but you need work on your algebra.
(1000x)(x) = 1E-14
1000x^2 = 1E-14
x^2 = 1E-14/1E3 = 1E-17
x = sqrt(1E-17) = 3.162E-9.
(1000x)(x) = 1E-14
1000x^2 = 1E-14
x^2 = 1E-14/1E3 = 1E-17
x = sqrt(1E-17) = 3.162E-9.
1 answer