A solution containing 29.00 mg of an unknown protein per 22.0 mL solution was found to have an osmotic pressure of 3.10 torr at 18 ∘C. What is the molar mass of the protein?

(3.10 torr* 22mL)=.682
I do not know what to do next

1 answer

First, I wouldn't start that way.
Convert torr to atm; i.e., 310/760 = pi = ?
pi = MRT. You know pi, R (0.0820), and T (in kelvin please). Solve for M = molarity.
Then M = mols/L.
You know M and L (or can convert to L), solve for mols.
Then mols = grams/molar mass. You know mols from above, the problem gives you mass in mg (convert to g), solve for molar mass.